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0 200 450 target 00 50 200 450 50 200 450 ansys 00

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Unformatted text preview: terial Properties ρ = 8000 kg/m3 ρw = 1000 kg/m3 Geometric Properties a=1m b=9m d=1m t = .03 m h = 30 m tangential drag coefficient = 0.3 Loading g = 9.807 m/sec2 Analysis Assumptions and Modeling Notes The static solution to this problem is best obtained by the “slow dynamics” technique with damping, since the buoy is initially subjected to free fall. An arbitrary time to steady state of 30 sec and 1.5 seconds per time step is ANSYS Verification Manual . ANSYS Release 9.0 . 002114 . © SAS IP, Inc. 1–349 VM158 selected for the slow dynamics. The mass damping value α determines the bouncing (if any) before the final steady state solution. An approximate α value is determined from F/MV where the force F = CV and damping C 2 = αM. The force F is the out-of-balance force (buoyancy force (1 / 4 ρw g π d b ) minus the buoy weight) for the initial position pushing the buoy into the water, M is the mass of the buoy, and V is an estimated average velocity (0.1 m/sec). Based upon these approximations, α ≈ 3 sec-1. Results Comparison Target Deflection , m ANSYS Ratio -.312 -.312 1.000 Figure 158.2 Displacem...
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