1 ft and a is the thermal diffusivity kc 001875 ft2hr

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Unformatted text preview: nd the periphery of the cylinder. To obtain the theoretical solution, equations 43 and 44 in F. B. Hildebrand, Advanced Calculus for Applications are used. Applying the temperature boundary condition and the requirement that T(r,Θ) should be finite and single-valued leads to the following solution: T(r,Θ) = T0 * (r/r0) * cosΘ. Results Comparison Mode = 1 (angle =0°) Target ANSYS Ratio Node 1 T, °F 0.0 0.0 - ANSYS Verification Manual . ANSYS Release 9.0 . 002114 . © SAS IP, Inc. 1–243 VM108 Mode = 1 (angle =0°) Target ANSYS Ratio Node 2 T, °F 20.0 20.0 1.00 Node 3 T, °F 40.0 40.0 1.00 Node 4 T, °F 60.0 60.0 1.00 1–244 ANSYS Verification Manual . ANSYS Release 9.0 . 002114 . © SAS IP, Inc. VM109: Temperature Response of a Suddenly Cooled Wire Overview Reference: F. Kreith, Principles of Heat Transfer, 2nd Printing, International Textbook Co., Scranton, PA, 1959, pg. 120, ex. 4-1. Analysis Type(s): Thermal Analysis (ANTYPE = 4) Element Type(s): Convection Link Elements (LINK34) Thermal Mass Elements (MASS71) Input Listing: vm109.dat Test Case Determine the temperature response of a copper wire of diameter d, originally at tempe...
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This note was uploaded on 12/09/2010 for the course DEPARTMENT E301 taught by Professor Kulasinghe during the Spring '09 term at University of Peradeniya.

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