Thermal analysis with phase change antype 4 2 d

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Unformatted text preview: mperature distribution in the cylinder for two cases: • k = constant, (i.e. C1 = 0) • k = k (T). Figure 102.1 Cylinder Problem Sketch Material Properties C0 = 50 Btu/hr-ft-°F C1 = 0.5 Btu/hr-ft-°F2 Geometric Properties ri = 1/2 in = (1/24) ft ro = 1 in = (1/12) ft Loading Ti = 100°F To = 0°F ANSYS Verification Manual . ANSYS Release 9.0 . 002114 . © SAS IP, Inc. 1–230 VM102 Analysis Assumptions and Modeling Notes The axial length of the model is arbitrarily chosen to be 0.01 ft. Note that axial symmetry is automatically ensured by the adiabatic radial boundaries. The problem is solved in two load steps. The first load step uses the constant k. The MP command is reissued in the second load step to specify a temperature-dependent k. Results Comparison Target[1] T, °F Ratio Node 2 first load step T, °F (k = k(T)); second load step 73.8 73.7 1.000 Node 3 51.5 51.5 1.000 Node 4 32.2 32.2 1.000 Node 5 15.3 15.2 0.99 Node 2 (k = constant); 1. ANSYS 79.2 79.2 1.000 Node 3 59.6 59.5 1.000 Node 4 40.2 40.2 1.000 Node 5 20.8 20.7 0.99 Based on a numerical relaxation method. ANSYS Verification Manual . ANSYS Release 9.0 . 002114 . © SAS IP, Inc. 1–231 VM103: Thin Plate with Central Heat Source...
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