Mid-Term Solution - EEC5180 Fall 61008 Ehgmm ELMhOM?flM¢w{MM 70”“ Exam Sobfions kecwam Cow“ fl 07c Car‘l‘ndn‘cal Coopde-~ af a¢ a

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Unformatted text preview: EEC5180 Fall 61008 \ Ehgmm%%% ELMhOM?flM¢w {MM} 70”“ Exam Sobfions) kecwam Cow“; \\ fl 07c, Car‘l‘ndn‘cal Coopde -~\ \\ af , a¢ , a; Sp CooQJA‘rUJI: A EFF/Rim? V0319~"‘?8‘ \ A "A . "A A Pmbi- b) 1) 32-01: ; <9? 0% “3”” a) 0" *Oflzz’gi 4)(01‘X6§9>@ 5) é)(?1x@) x 53 303.0%):1; :01’01 ~04 "\ ._ . ’ 2» x0920; if) fi-Efimo; 9>7>><Ei$zaa a)'a?xca73xa§> __\ __\ = fxT20~ w) Lie-(hp :0; ID @XQZ—a} J 14) 25.04950. ) la) KNEW?” 14> Lam—3M5; :fir- fir = 5743 x53; 1 i, I 0; Mb 2 Sobfion: l) Transwh Cgtmcm‘ml Coonhwt; (simskar a»; Hm sw1,:.m> \‘7 TEAM”, 41%) = EYE? ’F ENE +353 32f.af :Qa‘i+lb?j ~> 2 fiua?) +’a—;'a\r\ Cos? +C+ Shflp) (1): ardflnfiaé : ardflnl 345°; Sth: 00395:? y TWA/bear?) u) Szmflarlga, We kawa, —A ——\ “fl “'4 A E : 1; 0¢=Clflx+\afl+l~ w a .. A A A A ~ 01-0? + G‘a'a‘? 2 (\smm + 06393 2 (. smha)+(wwb)=0 iiOE§=E%=1; iv) YEW/95%): Aria? +55 a) TWnSJ‘w +0 s‘pmm COWNL; We“? 84 i) ECY/GICP) = Era? +Eofi9+E¢Ep ' ‘22 __ _ A A fl A ' 306;! Hit“: C\01+\63+Ia73>-0r ; —— "-3 A “A AN 1 :w“; -’ Ox~0r -"" a. , r» Sb-k 0‘8 0r+ %0r 2‘ Cosgzfil;fishe:g 23”“ +8‘m99n +6039 ' _ «u _ :E.E E (P’WX 2+On',:%m 3 9+é'a+3 amps-4-1:. :21; AB 53 r— '1 5 *5 =T:N3 \) ’ ,. —*‘_ A \ te—E e'fi‘ag+a5-’5+®‘5§ 25659W+C®659n¢~sw9 -Lma Elia E '- 5'2 +3‘3 ’ 3 ~15. E- " 3 15 -0 “A —>~ A ——A-—5 F; o-A “M395: E'a : 01-0 +030? mam; = ~swp+wsf +0 2 O “A A Eur exp): {Bar 3 P(0/0/3) \lpfobal SON-HEN (Sim€\aer—k Hw €0HhWQ) 6 0k) 3 (9‘ a 4160K” i) To Fmd (LI/0mm &;JS PSASZJézza 7( (J 90 FinARap) 0 oPS ()leqs \ -A A A .A R99=Yp~ e :3, gyfa ‘V’mwmva: PS ,___. r... .. f alt? "N WHCH)‘ +0(- \/ <9~C—o a) 7g<0 CE V a", Jaw —m> v Veg-2F?— oleo< W+M+Ialf (Mm) \/ \[+o+ai3:,fS/.< z 1 VJ aeo M“? ’/J (11+(OMZW +4 C7 PM E 17 %7J \ A, ; ,avi— Er VV gag ::E_<’2’_ (#4) A v 2)“%<A Varan- 360 [W W2) azawzfiagfi. (FL ?///)r— w < ‘ N 01‘Jr(o(+la\)2 a?) A “M 72; . W6 0&8 00 83 Usmam GauSs's \aw §>T§mls : Q i) 1:05;in r9310“, 'tluzrafs Ylo ekecm chaqu 3mm Hm Swen -—~\'__% '4 (:21. IO ’ C/ml \-‘ELF)"‘ “if—x -: “3‘ 1:} §? (is ” Q kyyom ,trzc (5‘00 9) rm; (MP3 W355 Lam .T’i‘AS :73 {9&6}; :. 8k :7 r w um saw WA 5 Lumd‘mgfia (may :7 C/mz \ PL 4 V/ ark/Eb f ’" 3W“ 0% /|’V\~ “:X “ -—- B— ’Q r/ a “ xi -~ M ,,,,, —-—~ y x L /‘8 ° 9Z£¢f at) /YYL— *9 T? 07m 9:» , 31w mywc km W den:pr '7 UM WWW oi“ (103% C. 'E’UYWL :Curvmw swung? ...
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This note was uploaded on 12/13/2010 for the course ELECTRICAL EECS 180 taught by Professor Chens.tsai during the Fall '10 term at UC Irvine.

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Mid-Term Solution - EEC5180 Fall 61008 Ehgmm ELMhOM?flM¢w{MM 70”“ Exam Sobfions kecwam Cow“ fl 07c Car‘l‘ndn‘cal Coopde-~ af a¢ a

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