BSEC 9-22 - n=10 x=3 p=chance (.21) 10! = 1*2*3*4 10...

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217 19 18 20 1. total tirals is 10 2. probability of csuccess is 21% 3. Let x = #of successes Part A. P(X=3)=? P(X=3)=P(3) 10! / 3!(10-3)! (.21)^3 (1-.21)^10-3
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Unformatted text preview: n=10 x=3 p=chance (.21) 10! = 1*2*3*4 10 3!=1*2*3 0!=1 p(e1)=1-p(e) P(E)=1-P(E1) P(X<=3)=P(0)+P(1)+P(2)+P(3)...
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This note was uploaded on 12/09/2010 for the course BUS 2313 taught by Professor Zhang during the Fall '10 term at East Central.

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