BSEC 9-17 - Condition 1 Each P(Xi should be between 0 and 1...

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Explanations: 1. Random variable X has 4 possible values to take in this case. X1 X2 X3 X4 2. P(X1) = 0.28 indicates there is a 0.28 probability (28%) for the random variable X to take the possible value X1=5
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Unformatted text preview: Condition 1 Each P(Xi) should be between 0 and 1. Condition 2 The summation of all P(Xi)’s added together should be equal to 1....
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