Unformatted text preview: P(X)=u^x*e^u/x! A. P(1)=0.6^1*2.71828^0.6/1! =0.6*.5488 =0.329 (32.9%) B. P(x<=1)=P(0)+P(1) P(0)=0.6^0*2.71828^0.6/0! = 1*0.5488/1 =0.5488 0.329+0.5488=0.8778 (87.78%) Part A = 0.329 Part B = 0.8778 C. P(X>1)=1P(X<=1) = 10.8778 = 0.1222 (12.22%)...
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 Fall '10
 Zhang
 Business, Probability theory, 12.22%, let x=number, 32.9%

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