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Unformatted text preview: inches. B) P(66<X<72)=? = P(66Ux/Ox< XUx/Ox < 72Ux/Ox) = P(6669.6/3.0 < Z < 7269.6/3.0) = P(3.6/3.0 < Z < 2.4/3.0) =P(1.20 < Z < 0.80) = P(Z < 0.80) P(Z < 1.20) +0.8=+0.8+0.00 = 0.7881 0.1151 = 0.6730 There is a 0.673 probability that the height of the randomly selected guy goes between 66 and 72 inches C) P(X>72)=? P(XUx/Ox > 72Ux/Ox) P(Z>7269.6/3.0 P(Z>2.4/3.0) P(Z>0.80) =1 the unshaded area = 1P(Z<0.80) = 10.7881 = 0.2119 There is a 0.2119 probability that the height of a randomly selected guy is over 72 inches. A)0.1151 B)0.673 C)0.2119...
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This note was uploaded on 12/09/2010 for the course BUS 2313 taught by Professor Zhang during the Fall '10 term at East Central.
 Fall '10
 Zhang
 Business

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