BSEC 10-25

# BSEC 10-25 - 3rd test ch 6 7 case A o=0.10 Zo/z=1.645 case...

• Notes
• 2

This preview shows pages 1–2. Sign up to view the full content.

3 rd test, ch 6 & 7 case A, o=0.10 Zo/z=1.645 case B, o=0.05 Zo/z=1.96 case C, o=0.01 Zo/z=2.575 318 38 46 41. Known that: 1. The population ={repair costs of all broken washing machines} The population mean U (i.e., the average repair cost of all broken machines) us unknown. 2. Sample size, n=40 Sample={x, x1, x2, x3, …} 3. Sample mean X_=\$120 4. sample standard deviation, s=\$17.50 (X1-x_)^2+(X2-x_)^2….(X40-x_)^2/40-1 5. Confidence level is 1-o=0.95 (95%), o=0.05 The 95% confidence interval for the unknown population mean U (the unknown average repair cost of all broken washing machines) is given by: 120+-(Z0.05/2)*17.5/sqrt40 120+-(1.96)17.5/6.225 120+-5.42 114.58, 125.42 we’re 95% confident that the unkown populaton U (the unknown average repair cost of all broken machines) lies betweem 114.58 & 125.42

This preview has intentionally blurred sections. Sign up to view the full version.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 39. Known that: 6. The population ={calorie reading of all 8 oz servings} The population mean U (i.e., the average calorie reading of all 8 oz servings) us unknown. 7. Sample size, n=31 Sample={x, x1, x2, x3, …} 8. Sample mean X_=99.3 9. sample standard deviation, s=41 (X1-x_)^2+(X2-x_)^2….(X40-x_)^2/40-1 10. Confidence level is 1-o=0.90 and 0.95 The 90% confidence interval for the unknown population mean U (the unknown average calorie reading of all 8 oz servings) is given by: 99.3+-(Z0.1/2)*41.5/sqrt31 99.3+-(1.645)41.5/5.567 99.3+-12.263 87.037, 111.563 we’re 90% confident that the unkown populaton U (the unknown average calorie reading of all 8 oz servings) lies betweem 87.037 & 111.563 38. 90% 21.99,24.41 95% 21.76, 24.64 46. 99% 97.79, 116.31...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern