Stat3022HW2 - outliers Problem 1.111 A)The mean is C and...

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Homework 2 Stat 3022 February 5, 2010 1.57 > hist(CRP) > boxplot(CRP) > summary(CRP) Min. 1st Qu. Median Mean 3rd Qu. Max. 0.000 0.000 5.085 10.030 9.420 73.200 Histogram of CRP CRP Frequency 0 20 40 60 80 0 5 10 15 20 25 30 0 20 40 60 We can see that there is a sharp right skey in the historgram from the plots. Mainly the histogram. 1.62 summary(over65) Min. 1st Qu. Median Mean 3rd Qu. Max. 5.70 11.70 12.75 12.54 13.48 17.60 The IQR=1.8. So 1.5*IQR=2.7. So Q1-2.7=9 and Q3+2.7=16.2. We can see that Alaska and Florida are outliers along with Utah. Problem 1.80 Group ¯ X s 1 23.75 5.06 2 14.08 4.98 3 15.77 5.76 1
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group1 group2 5 10 15 20 25 30 5 10 15 20 Histogram of group1 group1 Frequency 15 20 25 30 35 0 1 2 3 4 Histogram of group2 group2 Frequency 0 5 10 15 20 0 1 2 3 4 5 Histogram of group3 group3 Frequency 0 5 10 15 20 25 0.0 1.0 2.0 3.0 The histograms show that logging seems to reduce the number of trees per plot and that recovey is slow. The box plot shows that there are no extreme
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Unformatted text preview: outliers. Problem 1.111 A)The mean is C, and the meadian is B ( the right skew pulls the mean to the right). B) Mean A, median A C) Mean A, median B (the left skew pulls the mean to the right). 1.114 The middle 95% fall within two standard deviations of the mean or between 234 and 298 days. The shortest 2.5% of all pregnancies are shorter than 234 days. 1.122 25% of of the observations fall below -.6745 (qnorm(.25)) 35% of the ob-servations fall above .3853 (qnorm(.65)). 1.140 A) The quartiles for a standard normal dist are ± . 6745 (qnorm(.25),1norm(.75)) 2 B) X . 25 = μ + σ * -. 6745 and X . 75 = μ + σ * . 6745 C) X . 25 = 255 . 2 and X . 75 = 276 . 8 3...
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