Exam+2--Spring+2005 - I \ Spring2005 Exam IIA...

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I \ @ Spring 2005 Genetics 305 Exam II, form A Spring 2005, June 2 Section (circle one): Etb II)#: \- Exam IIA Please putyorn name on the top of all exam psges, including this page. Each question has one most correct answer. You may r$e a pencil when working on the exam, brt oilrt*l a^*trs mutt be .arlnd on this front pagt in pen If you have any questions, please ask a proctor. Part I: Multiple Choice - 90 points Circle the correct arurwer for each question. 4 /2 4 ./4 ,a{ 4 ^'/7 4 4o a b c@ e -lt. "G)c d e 4z @W%^ d e 4r rG) c d e .t4 a bG) d e -'ls a b@ d e ,'-G a b c@e n O c d e 4s a b c dO .=\\ a(! c .d e -fr bAd e /l- a (!, c d e a b c d@ c@e a @ c d e Hb@a e a b cQl e a@c d e b@o e ,"f, ,4 ,t/6 '-n 4E ,49 40 22 -Ca 44 ln\ L b c(! e p'u@a e bed e b@d e a b @ d e /- a b c,(9e a af"@" z.-\ \--/ / (a)b c d e \-/ r\ a(b)c d e a b c dG 4 /2 Pari II: True or False l0 c F T o If you feel some questions or answers warrant more lengthyg6mmeng please mark the test pages and then indicate on this page which qo.rtio* we shojd'look over: Plecne check questiorus: when you are finished" submit both the answer sheet and your exam.
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used to infect the bacterial cell. Sometime after infection, the radioactivity was measured outside in the ghosts of phage and inside of bacterial cell to see which component of the phage entered the bacterial cell. You are asked to do a similar experiment and you are given radioactive isotopes of P, S, C, N and H. Which of the following is expected to happen? [P=phosphorous ; S =sulfuri C=c arlon N=nilro gen H=hydrogen] tKs,Ae zu'fs,6n tn+lo b"#h b'orh P and N will be seen inside the bacteria whereas S, C and H will be seen outside the bacteria. S and C will be seen P, N, and H will be seen outside bacteria. P will be seen only inside of the bacteria S, C, N, and H are seen both inside and outside P will be seen only inside the bacteria, S will be seen only outside the bacteria and C, N, and H will be seen e. P and N will be seen only inside and S, C, and H will be seen only outside of 2.) The following ratios are calculated for a double stranded DNA molecule. \ / / (9 a 1. (A+T) / (G+C) 2. (A+G) / (C+r) 3. efd e0 3Da'o 4. (G+T) / (A+C) 5. A/G Which of these base ratios always equals l? ''.<- nn ''6-u' .{ @ w ,{ / I,2 and 3 only 2,3 and4 only 2 and 3 only 3 and 5 only 2,4 and 5 only (;+ *r [n." = C+ T \irl X3Y H+q , I **- I rl k-*T 6,=L :VIX It 'l
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f:r froA, ExamII-FormA *"*" Lu5nl tv, + itochondria from yeast are isolated, theirDNA was subjected to reassociation kinetics, anatne U ..n"Cot curve was generated. It is compared with the Cot curve of E. coli genome as shown in the following grap[. E. coli genome size is known to be 4 x 106 base pairs. Percent Single Stranded 15.0 Loe Cot Value 5.0 which of the following tr @ith the given data? d: In both E. coli, and yeast mitochondria, the genome is same as genome complexity. T b. The genome complexity,of,*uu fr:3. .&l*al genome is higher than that of the E. coli genome.
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This note was uploaded on 12/12/2010 for the course BIOL 305 taught by Professor Zhang during the Fall '10 term at University of Michigan.

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Exam+2--Spring+2005 - I \ Spring2005 Exam IIA...

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