Assignment2_solutions

# Assignment2_solutions - COSC 3213 Computer Networks...

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COSC 3213: Computer Networks Assignment # 2 - SOLUTIONS Winter 2005 Problem 1: (8x10)inch 2 * (800x800)pixels/inch 2 * 8 bits/pixel = 409.6 Mbits per picture (8x10)inch 2 * (800x800)pixels/inch 2 * 24 bits/pixel = 1.228 Gbits per picture Problem 2: Note: SNR in dB = 10 log 10 (SNR on a linear scale) a. BW = 2.4kHz, noiseless channel, M = 16 C = 2 × 2400 × log 2 (M) = 19,200 bps. b. BW = 2.4kHz, SNR = 20dB or 100 on linear scale C = 2400 × log 2 (1+100) = 15,979 bps. c. BW = 3.0kHz, SNR = 40dB or 10 4 on linear scale C = 3000 × log 2 (1+10 4 ) = 39,863 bps. Problem 3: a. The time taken to fully transmit and receive a packet of length L is composed of a propagation delay T p and a transmission delay T t : T = 100ms = T p + T t The propagation delay is obtained by dividing the length of the channel 1 by the signal speed: T p = l/ c = 4800 km / 200,000 km/s = 24ms Accordingly, T t = 100ms – 24ms = 76ms = L / R Hence, the data rate on the given channel turns out to be: R = L/T t = 80,000 bits / 76 ms = 1.05 Mbps Based on the Nyquist Channel capacity theorem, B = R /2 500 kHz.

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• Fall '10
• A
• Computer Networks, Bit rate, Orders of magnitude, English Channel, Kilometre, The Signal, Phase-shift keying

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