HW7solutions

# HW7solutions - So I ‘4 ‘I f o n ECE604 Homework 7 Out...

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Unformatted text preview: So I ‘4 ‘I- f o n ECE604 Homework 7 Out: Tuesday, March 2, 2004 (Session 15) Due: Tuesday, March 9, 2004 (Session 17) [Students with tape delays: due according to session number] Problem numbers are from the text by Ramo, Whinnery and Van Duzer(3":1 edition, 1994). (Note: for your solution you may assume that the material between the inner and outer conductors is air.) 1) 3.13b 2) 5.2g 3) 5.2h 4) 5.5a 5) 5.5d 6) 5.5e 7) 5.6a 4...... ‘ ‘ h I #6 ﬁght-gm“! *tﬁfﬁég >;\$H”J a-ké‘t? 3* 4. , , a .r ‘ a 0 ¢ Eat-la» J i ' (I ‘ “-95%? a ('2 Sgt-755W” )w’aer‘ y=m w *Jff'vtax, ‘7‘ i5" 9 43,44" 7-? 31%:{53‘4-3940' ' _ u WEI-ﬁ-i'l-i’] -_- %1f_a%:- , 1.: LONE), Q.—. are .a'a-ggmﬂb '13: 35 “a e933 5 m Wag 6.1mm; w. «ht leﬁﬁ OM- Wk) Meow- smug, mam Wayne. masm ‘em- «6* WM ' w; Kt: “\Eh‘tﬁ) 13"“ ‘0‘-°‘W*=s- “5’51“ ,vgw'somT‘h- _ ‘ mama. air digwfrk , a ﬂair 1". a LB MQOIQ) I. _ _ ' —-4 Reubu- «=- 5 .‘S Iwmf L“ 0‘) ,4‘ 9‘)‘ girl: R‘O “AK ‘10 60. to. Led \ao‘mo gain 7 - “So éomhnsﬁon 3% M main Cited ”Mum-d... \w Q-nsbumwp mm W ‘Wéﬂg 909%) 50 ohms thouﬁ 5.3m 2: 9s + Rs g gmuﬁ] _ ate; 9‘5 .5 {15‘ 31.: m4“. , am x65“ cw. 2- ~63 ,3. a- :Lb‘XJD— \mud , Uc'wg 5mg: gram 9115 \$.33 , . Q41?“- '\‘5 SKd'dntd 'b ﬁfﬁ - » (Zn-53m. "s Nam” Luv-565% (lﬂdui do“ noi' M. \$0 mﬁ‘lﬁ wﬂn harm-ﬁwa a1“ \“ﬁk—h‘ma 5.50:. From Eqs. 5-4- (4) and (5}, '3: 94/5. P" y5 «JV: 1w " w “ 8.»me 3.4V; “Ln-a- R‘- a a .._J’-—- Erma! Q EL v1 JW‘ 12%. in -.-:W ’1": 4,4 :31. V ‘1‘ x TL 3 a. '5. 45 a. sztl L? + I. ‘-’ L. . OOMbine‘and use I+Lt3= In (He-V“), we have 65.3%: wage-w +I.u—e-V1=)if: Lg‘t t=€z .a-V‘d I‘IBqu'Itc ‘Une any: 3%.+'Flt§ = ;&('"e—%) ‘%3P% =9 I-_== i. (Mme-W» (-EijéJe‘P‘F‘) Initial eondiﬁon: I._(o)-=o ==¥ A.*%;‘-ﬁ '=> IL#I+r-IL=L(1+%‘Ee—%ﬁ% 'PZ-icb 1‘6 '10 SxS-scjwmgm 'dcemmm‘ mg ‘39. wag-ma a." SMMHO“ A; M u‘un.‘ “madm- VCR-bag Afﬁr'tkm’c'ioﬁ one. “ﬁnding it» Hte. rig“? (Indie aﬁer‘bh‘leﬁgeoﬁmdinad. ham R?- Valiant} “9M ot'k ts'wb'tmc. can}; M'mdd \$3x\6"fx3no‘§xgw{-,ja¥ 'h‘g-M’. - and» m~mouul 5X10.‘KSXI&="\$M.\$0 (3km m-. e "Wg’. ”C in LA)“ mm?! “MM 09% end. IT|‘;%.*¥§; :6 '30 \va‘. 'A’t Econ/1:: 'U_ We: madam V4V¥§V39 0,. V+gr_v~v_=-v-k~V)-o M Ii "BI—'13!- H ' '30 '3. ‘ . \J M ‘3‘va V+0é arm end ctr-yeahgw-so n_.=o ' M h. (490*; V_ mfswldmpshgegggm V++V=o 3° V*s-Vay~d 1.3%,..1M M i ”We «enh- Note: Solution defines I in the short circuit in opposite sense compared to section 5.6. ...
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