HW7solutions - So I ‘4 ‘I f o n ECE604 Homework 7 Out...

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Unformatted text preview: So I ‘4 ‘I- f o n ECE604 Homework 7 Out: Tuesday, March 2, 2004 (Session 15) Due: Tuesday, March 9, 2004 (Session 17) [Students with tape delays: due according to session number] Problem numbers are from the text by Ramo, Whinnery and Van Duzer(3":1 edition, 1994). (Note: for your solution you may assume that the material between the inner and outer conductors is air.) 1) 3.13b 2) 5.2g 3) 5.2h 4) 5.5a 5) 5.5d 6) 5.5e 7) 5.6a 4...... ‘ ‘ h I #6 fight-gm“! *tfiffiég >;$H”J a-ké‘t? 3* 4. , , a .r ‘ a 0 ¢ Eat-la» J i ' (I ‘ “-95%? a ('2 Sgt-755W” )w’aer‘ y=m w *Jff'vtax, ‘7‘ i5" 9 43,44" 7-? 31%:{53‘4-3940' ' _ u WEI-fi-i'l-i’] -_- %1f_a%:- , 1.: LONE), Q.—. are .a'a-ggmflb '13: 35 “a e933 5 m Wag 6.1mm; w. «ht lefifi OM- Wk) Meow- smug, mam Wayne. masm ‘em- «6* WM ' w; Kt: “\Eh‘tfi) 13"“ ‘0‘-°‘W*=s- “5’51“ ,vgw'somT‘h- _ ‘ mama. air digwfrk , a flair 1". a LB MQOIQ) I. _ _ ' —-4 Reubu- «=- 5 .‘S Iwmf L“ 0‘) ,4‘ 9‘)‘ girl: R‘O “AK ‘10 60. to. Led \ao‘mo gain 7 - “So éomhnsfion 3% M main Cited ”Mum-d... \w Q-nsbumwp mm W ‘Wéflg 909%) 50 ohms thoufi 5.3m 2: 9s + Rs g gmufi] _ ate; 9‘5 .5 {15‘ 31.: m4“. , am x65“ cw. 2- ~63 ,3. a- :Lb‘XJD— \mud , Uc'wg 5mg: gram 9115 $.33 , . Q41?“- '\‘5 SKd'dntd 'b fiffi - » (Zn-53m. "s Nam” Luv-565% (lfldui do“ noi' M. $0 mfi‘lfi wfln harm-fiwa a1“ \“fik—h‘ma 5.50:. From Eqs. 5-4- (4) and (5}, '3: 94/5. P" y5 «JV: 1w " w “ 8.»me 3.4V; “Ln-a- R‘- a a .._J’-—- Erma! Q EL v1 JW‘ 12%. in -.-:W ’1": 4,4 :31. V ‘1‘ x TL 3 a. '5. 45 a. sztl L? + I. ‘-’ L. . OOMbine‘and use I+Lt3= In (He-V“), we have 65.3%: wage-w +I.u—e-V1=)if: Lg‘t t=€z .a-V‘d I‘IBqu'Itc ‘Une any: 3%.+'Flt§ = ;&('"e—%) ‘%3P% =9 I-_== i. (Mme-W» (-EijéJe‘P‘F‘) Initial eondifion: I._(o)-=o ==¥ A.*%;‘-fi '=> IL#I+r-IL=L(1+%‘Ee—%fi% 'PZ-icb 1‘6 '10 SxS-scjwmgm 'dcemmm‘ mg ‘39. wag-ma a." SMMHO“ A; M u‘un.‘ “madm- VCR-bag Affir'tkm’c'iofi one. “finding it» Hte. rig“? (Indie afier‘bh‘lefigeofimdinad. ham R?- Valiant} “9M ot'k ts'wb'tmc. can}; M'mdd $3x\6"fx3no‘§xgw{-,ja¥ 'h‘g-M’. - and» m~mouul 5X10.‘KSXI&="$M.$0 (3km m-. e "Wg’. ”C in LA)“ mm?! “MM 09% end. IT|‘;%.*¥§; :6 '30 \va‘. 'A’t Econ/1:: 'U_ We: madam V4V¥§V39 0,. V+gr_v~v_=-v-k~V)-o M Ii "BI—'13!- H ' '30 '3. ‘ . \J M ‘3‘va V+0é arm end ctr-yeahgw-so n_.=o ' M h. (490*; V_ mfswldmpshgegggm V++V=o 3° V*s-Vay~d 1.3%,..1M M i ”We «enh- Note: Solution defines I in the short circuit in opposite sense compared to section 5.6. ...
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