HW8solutions

HW8solutions - 5‘ I a#3 fl ECE604 Homework 8 Out Tuesday...

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Unformatted text preview: 5‘ I a {#3 fl ECE604 Homework 8 Out: Tuesday, March 9, 2004 (Session 17) Due: Tuesday, March 23, 2004 (Session 19) [Students with tape delays: due according to session number] Problem numbers are from the text by Ramo, Whinnery and Van Duzer (3rd. edition, 1994). l) 5.7c 2) 5.7d 3) 5.8a 4) 5.80 5) 5.8d 6) 5.8e 7) Consider a parallel plate transmission line made of perfectly conducting plates. The plates are 5mm wide and spaced by 250 um and the medium between the plates is air. The characteristic impedance of the transmission line is denoted by 20. At one end the transmission line is connected to a short circuit, while at the other end the transmission line is connected to a matched load (RL = 20). The transmission line is driven by a current sheet sinusoidally varying at a frequency of 10 GHz, separated a distance d from the short circuit. The total length of the transmission line is 10 cm. perfectly conducting plates (extend 5 mm into paper) current sheet ,I' (extends 5 mm into paper) I” short circuit z=d z=10cm a) Where should the current sheet be placed to maximize the power delivered to the load resistor RL? (What is the value of d?) A short answer is acceptable provided it is justified. b) Now the short circuit at z = 0 is replaced by an open circuit. Now where should the current sheet be placed to maximize the power delivered to the load resistor? 57c Fm 8055215, 3;: 1-", :32 _ ..A . I ‘ I ‘ " EL; 2...) ‘° ‘2' a»: 52.42.; 3&3“ and M‘ou." 1% MOktMQc; *0 \‘M_ L 9/5334; ~+ “39% a a 57M: \ua) -.-.\J_\_e, +\L_e (5 In a“)? _ 2-, ‘2: “3 » 1(3): L XV+€ - 3=1+e ‘o ..\L‘ ' ., _ \I'. _ a 31" ‘5” PI: 1;;— ’2 = 7"7Dv \Pv\e 1*\' V‘Vlao + ' 518a: _ eL—zo _ (loo+'&\°0)—§'0 _7+4} = .9; 59.3.7" (0— %Hz-° moqmo) +570 |5 8: ""‘P‘ = \-\-‘6Q‘_. -= 4‘97' \-Ip\ was _ \, ____._.1_~2-,,\+ __,_é'3K-‘+-$)T X =[ 3176 $99313. - 2.1V _..¢,w= 403‘ ,so (0: .2 \.\’x)+'l“£= '5“ V V l .—\o%° .251Q6* ‘3)“. 518d; Impedancq seen mugrhr wowz'm ’— 2° grorfi‘ 0%" EL \‘3 75;: a T " 2.8%; =%, I ° W“ “M” ram 2 or m 11%. a 1.; %Q%\_-\-E:' %._%L 1* $0 ~2ta'ié.’ ' ‘ \ lg £933, , an: _vzb (a «game. rethan ,) 5186.1 F§r$‘\‘ dwzngcnnnefir he “an Kn 9'”on Omd des‘xzh abuar‘V<r_wavz ’rv-omsgurmgy-fi-o witch '“M. WB‘nOfiOn-J 2L on +mvs-Qomerflsn 76;: 1‘2 5 LC; =g01g° %\=5S-L\ n— —. £L 26‘ ‘ FM- oihey Mme-‘29., ; , e 2;: %‘ \asm GEM”) Hawk? 4.3] 7 7 (continua on next Page) ’~ A + A‘ - — It It : $4.4:ka “' L a” 3 *1 Ea ’\ ". <3\<(3-a93 M? W 1 Wk. Cam v1 :‘ C A r “4* ')k<}*‘2u) T a. \)‘L a ’7. -———‘ go Hem : M «K 4m wmk {3 «MM [owl 9 may“? rfilzofijvcxw oh Mgzmz. M92, a IND“ (0‘9" WW+VQ\ \OOU'AJLMII AA" C(f‘cwq‘ ‘ V _. . «_ 4‘ ‘ «am. Mm. a w. m «Ey‘vw: :{ A A - . ~- re A K V; ‘ ’QJV1.;bm\€§ ) ii- %0* CBS V A t « A+ 3w» MM who): vim); pm " A 3 2 :30) Wk “I, T. "‘ A Hon» V14 .._ avu— 635609) 2 I" in“; 7a A 4 Va ,_ 2g flu @éflkfl __ -‘%o b 2. s“:n{w 0% x\ .- 3 03+ (b.1933 I 53:, A ~$§flm§l —3 (b3 i, E was, [ §7n(k&) £3; «1‘5. e ,fihglamfl ‘6 4nd 331% v; Wfibu; ‘ 670L800 ,- LUQ— Cé-m s-MFJZL‘ ‘V’dM ‘Hm‘s M at Show“. 1 (QMvMa 4kg T.L..s sin -—- \r,4..)-(—La_ ng9~sacfim «wk her mac J6 TL W L;_ Qmw, :Fn Pf§ A4 7 f 26%;: .2 EL 5 /I‘;~& ) burg/(AL, iw‘lffi‘i‘e- At” fixbé/u’vj; 5% 62651415.) ‘ /’-"“"‘“ . W...— “~— ‘ ._ .V _-— A M w-—‘. r. . -.( ‘ w . W’L'g’dif CéUt/Wf ALWQ l'zfjflz. flow, flc Cit/W” [W74 (fnefi) “£62,, Auk} AA. (ILA 0/3)” 3% WM f‘”/9»ic€¢m“* ww- /« jrl/eo fézjfl I. go 2L (13.5ch ) ) WALELfO 26 COSkcJ? . v @ Fm [(4:91 (:4 MT/L) , a.“ 0/4,“ cirruz+. ‘Tflrr is Jay-7" ?UM-744\wmm» kafLJWW Clmcaff‘ MK .743 MM?"‘f‘jz&/0W we AM, M ww‘ M 7/7 7L [fir/é - Mum»): » ('5') Med is 52/: of“ Cr‘i‘Cu/%¢W£3 =0- 09% ding/5511M 6% mic/0W chgpj aw— ,é/Iww fiML [Maw/209.44 Ii (lat/IVWJVZO AaJ/ZJAA f c/‘VC‘JML Arc/‘1' (PM own *0 m W Sam/Iota ...
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This note was uploaded on 12/12/2010 for the course ECE 604 taught by Professor Staff during the Spring '08 term at Purdue.

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HW8solutions - 5‘ I a#3 fl ECE604 Homework 8 Out Tuesday...

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