20ft - (b) We have ...(3). Differentiate (3) with respect...

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We have ...(1). Differentiate (1) with respect to time, we get ...(2). Given x = (1/2)(90ft) = 45 ft, then Since the batter is approaching the first base, then dx/dt =-24 ft/s. Putting the data into (2), then dr/dt = -10.7 ft/s.
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Unformatted text preview: (b) We have ...(3). Differentiate (3) with respect to time, we get ...(4). Given x = (1/2)(90ft) = 45 ft, then Since x is increasing, then dx/dt = 24 ft/s. Putting the data into (4), then dr/dt = 10.7 ft/s....
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