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Week 11 Mon Nov 8a

# Week 11 Mon Nov 8a - Posted after class WEEK 11 Mon Nov 8...

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Posted after class WEEK 11 – Mon, Nov 8 Lower Estimates - (1 – α)100% Confidence Level One-Sided Confidence Intervals Guidelines from the Centers for Medicare & Medicaid Services state “In most situations, the lower limit of a one-sided 90 percent confidence interval should be used as the amount of overpayment to be demanded for recovery from the physician or supplier.” CI for µ - Case σ is known Book (N indefinitely large) N specified – Correct Formula Discuss limitations. CI for µ - Case σ is unknown Book (N indefinitely large) N specified – Correct Formula Use with n – 1 df (degrees of freedom). If you use the t-table in the book and the df value is not in the table, go to the row above the missing value. Discuss limitations. CI for p (appropriate for large n) Book (N indefinitely large) N specified – Correct Formula Discuss limitations. Example of Lower Estimate . The x-characteristic of a population of size 900 has unknown mean and unknown standard deviation. A 90% lower estimate is needed for the population mean. A simple random sample of 48 units is selected. The sample has average 36.54 and standard deviation 22.45. Calculate the lower estimate. Ans. 32.34 1

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Upper Estimates - (1 – α)100% Confidence Level One-Sided Confidence Intervals CI for µ - Case σ is known Book (N indefinitely large) N specified – Correct Formula Discuss limitations. CI for µ - Case σ is unknown Book (N indefinitely large) N specified – Correct Formula Use with n – 1 df (degrees of freedom). If you use the t-table in the book and the df value is not in the table, go to the row above the missing value. Discuss limitations. CI for p (appropriate for large n) Book (N indefinitely large) N specified – Correct Formula Discuss limitations. Example . The 600 parts in a bin has an unknown proportion p of parts that will not pass inspection. A simple random sample of 150 parts from the bin is inspected and it is found that 12 of the 150 will not pass inspection. A 95% upper estimate is needed for the number of parts in the bin that will not pass inspection. Calculate the upper estimate. Ans. The upper estimate for p is 0.1116 which multiplied by 600 gives the answer 66 or 67 parts.
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