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~
number
must be rounded
to two
~tfigures.
Table 1.4
EnglishMetric
Equivalents
zth
1 m = 1.094 yd
2.54 em
=
1 in
1 kg
=
2.205 Ib
453.6
g
=
lIb
1 L
=
1.06 qt
1
ft
3
=
28.32 L
e
1.6
Dimensional
Analysis
17
Solution
a.
The result
is 1.71
X
10
4
,
which
has three significant
figures because
the term with
the least precision
(1.05
X 10
3
)
has three significant
figures.
b.
The result
is
7
with no decimal
point
because
the number
with the least number
of
decimal
places (21) has none.
c.
R
=
PV
=
(2.560)(8.8)
T
275.15
The correct
procedure
for obtaining
the final result can be represented
as follows:
(2.560)(8.8)
22.528
275.15
=
275.15
=
0.0818753
= 0.082 = 8.2
X
10~2 =
R
The final result must be rounded
to two significant
figures because
8.8 (the least pre
cise measurement)
has two significant
figures. To show the effects
of rounding
at in
termediate
steps, we will carry out the calculation
as follows:
(2.560)(8.8)
275.15
Rounded
to two
significant
figures
!
23
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 Organic chemistry

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