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Unformatted text preview: 1.7 Temperature 23 Fahrenheit ta Celsius o Kelvin
(Ql 98.6°F ~ n; , ?OC ?K 66.6°F 66.6°F x ~:~ = 37.0°C 37.0 + 273.15 K = 310.2 K 32°F O°C  273.15 K 1.10
.=!7". body temperature on the FahrenCelsius, and Kelvin scales. Solution
Rather than simply using the formulas to solve this problem, we will proceed by thinking it through. The situation is diagramed in Fig. 1.10. First, we want to convert 98.6°F to the Celsius scale. The number of Fahrenheit degrees between 32.0°F and 98.6°F is 66.6°F. We must convert this difference to Celsius degrees: 5°C 66.6°F X 9°F Thus 98.6°F corresponds to 37.0°C. Now we can convert to the Kelvin scale:
ician taking the temperature
,~ = 37.0°C of a TK = Tc + 273.15 = 37.0 + 273.15 = 310.2 K Note that the final answer has only one decimal place (37.0 is limiting).
SEE EXERCISES 1.53, 1.55, AND 1.56 XAMPLE 1.12  One interesting feature of the Celsius and Fahrenheit scales is that 40°C and 40°F represent the same temperature, as shown in Fig. 1.9. Verify that this is true. Solution
The difference between 32°F and 40°F is n°F. The difference between O°C and 40°C is 40°C. The ratio of these is
= nOF 8 8 X X 9°F 5°C = 9°F 40°C 5°C as required. Thus 40°C is equivalent to 40°F.
SEE CHALLENGE PROBLEM 1.57 ...
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This note was uploaded on 12/13/2010 for the course CHEM 2301 taught by Professor Bill during the Spring '10 term at South Texas College.
 Spring '10
 bill
 Organic chemistry

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