Scan_Doc0029 - 1.7 Temperature 23 Fahrenheit ta Celsius o...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1.7 Temperature 23 Fahrenheit ta Celsius o Kelvin (Ql 98.6°F ~ n-; -, ?OC ?K 66.6°F 66.6°F x ~:~ = 37.0°C 37.0 + 273.15 K = 310.2 K 32°F---- O°C -------- 273.15 K 1.10 -.=!7". body temperature on the FahrenCelsius, and Kelvin scales. Solution Rather than simply using the formulas to solve this problem, we will proceed by thinking it through. The situation is diagramed in Fig. 1.10. First, we want to convert 98.6°F to the Celsius scale. The number of Fahrenheit degrees between 32.0°F and 98.6°F is 66.6°F. We must convert this difference to Celsius degrees: 5°C 66.6°F X 9°F Thus 98.6°F corresponds to 37.0°C. Now we can convert to the Kelvin scale: ician taking the temperature ,~ = 37.0°C of a TK = Tc + 273.15 = 37.0 + 273.15 = 310.2 K Note that the final answer has only one decimal place (37.0 is limiting). SEE EXERCISES 1.53, 1.55, AND 1.56 XAMPLE 1.12 - One interesting feature of the Celsius and Fahrenheit scales is that -40°C and -40°F represent the same temperature, as shown in Fig. 1.9. Verify that this is true. Solution The difference between 32°F and -40°F is n°F. The difference between O°C and -40°C is 40°C. The ratio of these is --= nOF 8 8 X X 9°F 5°C =- 9°F 40°C 5°C as required. Thus -40°C is equivalent to -40°F. SEE CHALLENGE PROBLEM 1.57 ...
View Full Document

This note was uploaded on 12/13/2010 for the course CHEM 2301 taught by Professor Bill during the Spring '10 term at South Texas College.

Ask a homework question - tutors are online