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3.9 Balancing Chemical Equations 101 (NH4)2Cr207(S) ---+ Cr 2 0 3 (S) + Nz(g) + H 2 0(g) that the Roman numeral III means that Cr H ions are present. For a neutral compound, the formula must then be Cr203, since each oxide ion is 0 2 -. 2 ~ The unbalanced equation is 3 ~ Note that nitrogen and chromium are balanced (two nitrogen atoms and two chromium atoms on each side), but hydrogen and oxygen are not. A coefficient of 4 for H 2 0 bal- ances the hydrogen atoms: (NH4)2Cr207(S) ---+ Cr 2 0 3 (s) + N 2 (g) + 4H z O(g) ~X~H ~X~H Note that in balancing the hydrogen we also have balanced the oxygen, since there are seven oxygen atoms in the reactants and in the products. Reality Check:
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Unformatted text preview: The equation is balanced. Decomposition of ammonium dichromate. 2 N, 8 H, 2 Cr, 7 °---+ 2 N, 8 H, 2 Cr, 7 ° Reactant Product atoms atoms SEE EXERCISES 3.89 THROUGH 3.92 EXAMPLE 3.14 At lOOO°C, ammonia gas, NH 3 (g), reacts with oxygen gas to form gaseous nitric oxide, NO(g), and water vapor. This reaction is the first step in the commercial production of ni-tric acid by the Ostwald process. Balance the equation for this reaction. Solution 1, 2 ~ The unbalanced equation for the reaction is NH3(g) + OzCg)---+ NO(g) + H 2 0(g)...
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