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Scan_Doc0014 - 3.11 The Concept of Limiting Reagent 107 2 ~...

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Milk of magnesia contains a suspension of Mg(OHh(s). 3.11 The Concept of Limiting Reagent 107 2 ~ What are the moles of NaHC0 3 in 1.00 g? To find the moles of NaHC0 3 , we need to know the molar mass (84.01 g/mol). 1mol NaHC0 3 1.00 g...NaHe()3 X = 1.19 X 10- 2 mol NaHC0 3 84.01 g..NaHee)3 3~ What is the mole ratio between HCl and NaHC0 3 in the balanced equation? 1mol HCI 1mol NaHC0 3 4 ~ What are the moles of HCl? 1mol HCI 1.19 X 10- 2 ~ X = 1.19 X 10- 2 mol HCI 1~ Thus 1.00 g of NaHC0 3 will neutralize 1.19.X 10- 2 mol HCI. For Mg(OH)2 1 ~ What is the balanced equation? Mg(OHMs) + 2HCl(aq) ~ 2H 2 0(l) + MgCI 2 (aq) 2 ~ What are the moles of Mg(OHh in 1.00 g? To find the moles of Mg(OHh, we need to know the molar mass (58.32 g/mol). 1mol Mg(OH)2 1.00 ~ X ~ = 1.7l X 10- 2 mol Mg(OH)2 . 58.32 2 3~ What is the mole ratio between HCI and Mg(OH)2 in the balanced equation? 2 mol HCI
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