Scan_Doc0015 - 108 Chapter Three Stoichiometry To solve...

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108 Chapter Three Stoichiometry Bread Meat Cheese Sandwich Tosolvethisproblem, let's seehowmany sandwiches wecanmake with each component: 1sandwich 8 slices bread X = 4 sandwiches 2 slices bread Bread: Meat: 1sandwich 9 slices meat X = 3 sandwiches 3slices meat Cheese: 1sandwich 5 slices cheese X = 5 sandwiches I slice cheese How many sandwiches can you make? The answer is 3. When you run out of meat, you must stop making sandwiches. The meat is the limiting ingredient. See Fig. 3.9. What do you have left over? Making 3 sandwiches requires 6 pieces of bread. You started with 8 slices, so you have 2 slices of bread left. You also used 3 pieces of cheese for the 3 sandwiches, so you have 2 pieces of cheese left. In this example, the ingredient present in the largest number (the meat) was actually the component that limited the number of sandwiches you could make. This situation arose because each sandwich required 3 slices of meat-more than the quantity required of any
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Unformatted text preview: molecules react with each other to form products, considerations very similar to those involved in making sandwiches arise. We can illustrate these ideas with the re-action of Nz(g) and Hz(g) to form NH3(g): Nz(g) + 3H z (g) ~ 2NH 3 (g) Figure 3.9 Making sandwiches. /o-~·~.--------O-.'.~.~'~~ ...~----~----~-~-'\- . .• I ".' _, I , . . / I ' ./ :0'. 0.··. . ·.·.· ..... ·.... ·-.··· --\ "'"- ~ /' \ . / \ " .. ' . I , I "0'--. .-.~-" 0····· e. . • • •. / ", -.--/--'," ,' / "v"/ •.•. _----_/ ','-~---::.-,-~---.-.-----"""",;-",-./ " . ,'. '>-. . . • / ',. ........ / I , , I 1 \ \ \ 'V' 0""-> "-', +-.--./ ,. ./ '-----'"--'" .~ »> /// '. //-O·=;~~-·-', '.",'-. ./ e.: ',:; \ /0------/ "\.". ..,' '\ / '" 0··. . ·.. ' I.,,>. , I ',_. _ ~ , I" _ ~ <, . ...•. I . <> ~>-...... _---------------------------,-, \ ., ~-,--,-/ / / / 10. ....
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