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Unformatted text preview: scent attracts other bees to join the attack. How many molecules of isopentyl acetate are released in a typical bee sting? How many atoms of carbon are present? Solution Since we are given a mass of isopentyl acetate and want to find the number of molecules, we must first compute the molar mass: 7 mol C X 12.01!r = 84.07 g C 14 mol H X l.008!r = 14.11 g H 2 mol 0 X 16.00!r = 32.00 g 0 130.18 g This means that 1 mole of isopentyl acetate (6.022 X 10 23 molecules) has a mass of 130.18 g. To find the number of molecules released in a sting, we must first determine the number of moles of isopentyl acetate in 1 X 106 g:6 1 mol C 7 H 14 29 1 X 10 ~ X = 8 X 10 molC 7 H 14 2 130.18~ Since 1 mole is 6.022 X 10 23 units, we can determine the number of molecules: 6.022 X 10 23 molecules _ 8 X 109 ~ X = 5 X 10 1 ) molecules 1~...
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This note was uploaded on 12/13/2010 for the course CHEM 2301 taught by Professor Bill during the Spring '10 term at South Texas College.
 Spring '10
 bill
 Organic chemistry, Mole, Stoichiometry

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