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Unformatted text preview: T Write the ideal gas law, collecting the change variables on one side of the equal sign and the variables that do not change on the other. PV = nRT .7' '\ Change Remain constant Since nand T remain the same in this case, we can write PI VI = nRT and P 2 V 2 = nRT Combining these gives PIV I = nRT = P 2 V 2 or P I V I =P 2 V 2 We are given PI = 1.68 atm, VI = 7.0 mL, and V 2 = 2.7 mL. Solving for P 2 thus gives ( VI) (7.0 mt:) P 2 =-PI =---1.68 atm = 4.4 atm V 2 2.7 mt: Reality Check: Does this answer make sense? The volume decreased (at constant tem-perature), so the pressure should increase, as the result of the calculation indicates. Note that the calculated final pressure is 4.4 atm. Most gases do not behave ideally above 1 atm. Therefore, we might find that if we measured the pressure of this gas sample, the observed pressure would differ slightly from 4.4 atm. SEE EXERCISES 5.53 AND 5.54...
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This note was uploaded on 12/13/2010 for the course CHEM 2301 taught by Professor Bill during the Spring '10 term at South Texas College.
- Spring '10
- Organic chemistry