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Unformatted text preview: T Write the ideal gas law, collecting the change variables on one side of the equal sign and the variables that do not change on the other. PV = nRT .7' '\ Change Remain constant Since nand T remain the same in this case, we can write PI VI = nRT and P 2 V 2 = nRT Combining these gives PIV I = nRT = P 2 V 2 or P I V I =P 2 V 2 We are given PI = 1.68 atm, VI = 7.0 mL, and V 2 = 2.7 mL. Solving for P 2 thus gives ( VI) (7.0 mt:) P 2 =PI =1.68 atm = 4.4 atm V 2 2.7 mt: Reality Check: Does this answer make sense? The volume decreased (at constant temperature), so the pressure should increase, as the result of the calculation indicates. Note that the calculated final pressure is 4.4 atm. Most gases do not behave ideally above 1 atm. Therefore, we might find that if we measured the pressure of this gas sample, the observed pressure would differ slightly from 4.4 atm. SEE EXERCISES 5.53 AND 5.54...
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This note was uploaded on 12/13/2010 for the course CHEM 2301 taught by Professor Bill during the Spring '10 term at South Texas College.
 Spring '10
 bill
 Organic chemistry

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