Figure13_11 - E4 = D4*$A$4*$A$6/$A$8 Titration of 50 mL of...

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Cm = pM M Phi V (ligand) 0.04 1.3980 4.00E-02 0.000 0.002 Vm = 1.5364 2.91E-02 0.200 5.005 50 2.00 1.00E-02 0.667 16.667 C(ligand) = 3.00 1.00E-03 0.963 24.074 0.08 4.00 1.00E-04 0.996 24.906 Kf' = 5.91 1.22E-06 1.000 25.000 1.80E+10 7.00 1.00E-07 1.001 25.014 8.00 1.00E-08 1.006 25.139 8.86 1.38E-09 1.040 26.006 C4 = 10^B-4 Equation 13-11 D4 = (1+$A$10*C4-(C4+C4*C4*$A$10)/$A$4)/ (C4*$A$10+(C4+C4*C4*$A$10)/$A$8)
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Unformatted text preview: E4 = D4*$A$4*$A$6/$A$8 Titration of 50 mL of 0.04 M Ca 2+ with 0.08 M EDTA 5 10 15 20 25 30 35 2 4 6 8 10 Volume of EDTA added (mL) pM Excess metal Excess EDTA Sr 2+ K f ' = 1.9 x 10 8 Ca 2+ K f ' = 1.8 x 10 10 Ca 2+ equivalence point Sr 2+ equivalence point...
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This note was uploaded on 12/13/2010 for the course CHEM 215 taught by Professor Johnson during the Spring '10 term at Texas Brownsville.

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Figure13_11 - E4 = D4*$A$4*$A$6/$A$8 Titration of 50 mL of...

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