3.5-1 - x 2 3 3 f ± x = x 3 3 x 15 x 2 3 √ x 2 3 4 f ± x = x 3 15 √ x 2 3 jordan(lj5655 – 3.5 – Arledge –(55100 2 5 f ± x = x 3 3 x 2

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jordan (lj5655) – 3.5 – Arledge – (55100) 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points ±ind the value oF f ± (0) when f ( x )=( 1 - 6 x ) - 2 . 002 10.0 points ±ind the derivative oF f when f ( x )= ± x 9 / 2 +4 x - 9 / 2 ² 2 . 1. f ± ( x )=9 ³ x 18 - 16 x 10 ´ 2. f ± ( x )=1 0 ³ x 18 +16 x 10 ´ 3. f ± ( x )=9 ³ x 9 +4 x 9 ´ 4. f ± ( x )=9 ³ x 18 - 4 x 9 ´ 5. f ± ( x )=1 0 ³ 1+4 x - 18 x 9 ´ 6. f ± ( x )=1 0 ³ 1 - 4 x - 18 x 9 ´ 003 10.0 points ±ind the x -and y -intercepts oF the tangent line to the graph oF y =(4 x +4) 1 / 3 at the point (1 , 2). 1. x -intercept = - 4 ,y -intercept = 4 3 2. x -intercept = - 5 ,y -intercept = 5 3 3. x -intercept = - 19 4 ,y -intercept = 7 4 4. x -intercept = - 1 ,y -intercept = 1 3 5. x -intercept = - 4 ,y -intercept = 5 3 004 10.0 points ±ind p ( x )sothat f ± ( x )= p ( x ) f ( x ) when f ( x )= (3 + 5 x ) 4 (3 - 4 x ) 5 . 1. p ( x )= 6 - x 9+3 x - 20 x 2 2. p ( x )= 6+ x 9+3 x - 20 x 2 3. p ( x )= 20(3 + x ) 9+3 x - 20 x 2 4. p ( x )= 20(6 + x ) 9+3 x - 20 x 2 5. p ( x )= 20(6 + x ) 9+3 x +20 x 2 005 10.0 points ±ind the derivative oF f when f ( x )= µ x 2 +3+ 5 x x 2 +3 . 1. f ± ( x )= x 3 - 15 ( x 2 +3) x 2 +3 2. f ± ( x )= x 3 - 3 x - 15 (
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Unformatted text preview: x 2 + 3 3. f ± ( x ) = x 3 + 3 x + 15 ( x 2 + 3) √ x 2 + 3 4. f ± ( x ) = x 3 + 15 √ x 2 + 3 jordan (lj5655) – 3.5 – Arledge – (55100) 2 5. f ± ( x ) = x 3 + 3 x 2 + 15 ( x 2 + 3) √ x 2 + 3 006 10.0 points Find the derivative of y when y = cos(5 x ) cos x-sin(5 x ) sin x . 1. y ± =-4 sin(4 x ) 2. y ± =-6 sin(6 x ) 3. y ± = 4 cos(6 x ) 4. y ± =-6 sin(4 x ) 5. y ± = 4 cos(4 x ) 6. y ± = 6 cos(6 x ) 007 10.0 points Find the x-coordinates of all points on the graph of f ( x ) = 6 sin x + sin 2 x at which the tangent line is horizontal. 1. π 4 + 2 nπ, all integers n 2. π 2 + nπ, all integers n 3. π 2 + 2 nπ, all integers n 4. π 3 + nπ, all integers n 5. π 4 + nπ, all integers n 6. π 3 + 2 nπ, all integers n...
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This note was uploaded on 12/05/2010 for the course M 408N taught by Professor Gualdini during the Spring '10 term at University of Texas at Austin.

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3.5-1 - x 2 3 3 f ± x = x 3 3 x 15 x 2 3 √ x 2 3 4 f ± x = x 3 15 √ x 2 3 jordan(lj5655 – 3.5 – Arledge –(55100 2 5 f ± x = x 3 3 x 2

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