55. (a) The electric field between the plates is leftward in Fig, 24-52 since it points towards lower values of potential. The force (associated with the field, by Eq. 23-28) is evidently leftward, from the problem description (indicating deceleration of the rightward moving particle), so that q > 0 (ensuring that F → is parallel to E → ); it is a proton.
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This note was uploaded on 12/13/2010 for the course PHY 422 taught by Professor Rt during the Fall '10 term at NE Texas CC.