*This preview shows
page 1. Sign up
to
view the full content.*

57. Let the distance in question be
r
. The initial kinetic energy of the electron is
Km
v
ie
i
=
1
2
2
, where
v
i
= 3.2
×
10
5
m/s. As the speed doubles,
K
becomes 4
K
i
. Thus
∆∆
U
e
r
KK
K
K
m
v
ii
i
e
i
=
−
=−
−
2
2
4
43
3
2
π
0
ε
()
,
or
( )
2

This is the end of the preview. Sign up
to
access the rest of the document.