57. Let the distance in question be r. The initial kinetic energy of the electron is Kmviei=122, where vi= 3.2 ×105m/s. As the speed doubles, Kbecomes 4Ki. Thus ∆∆UerKKKKmviiiei=−=−−2244332π0ε(),or ( )2
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 12/13/2010 for the course PHY 132 taught by Professor Rw during the Fall '10 term at NE Texas CC.