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58. (a) Using
U = qV
we can “translate” the graph of voltage into a potential energy
graph (in eV units).
From the information in the problem, we can calculate its kinetic
energy (which is its total energy at
x
= 0) in those units:
K
i
=
284 eV.
This is less than
the “height” of the potential energy “barrier” (500 eV high once we’ve translated the

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