EEE445_hw11sln

EEE445_hw11sln - EEE 591/445 Homework 11 6.22. Solution 1....

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EEE 591/445 Homework 11 6.22. Solution 1. Analytical, using near resonance approximation  10 0 91 2 0 0 0 0 0 2 2 00 13 0 1 3.14185 10 rad/sec 2 (5 10 )(1000)(0.804 10 ) 25.2584 x/ 1 Let 2 (1 ) 1 0.086281 1( 2 ) 12 0 ) 1 (2 ) 1.60655 10 0.160655 pF in in in LC Q R Z Q x jC j R eZ Z x Qx QRx mZ Cx Q x CF f         0 ) 4.569GHz 2 x Solution 2. Smith chart (skipped) Solution 3. ADS confirmation
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7.2. 14 14 11 20log 20log0.1 20 dB 0.1 20log 20log 6.02 dB .05 90 20log 20log .05 90 26.02 dB 20log 20log0.5 26.02 dB C D S IS RL S     In summary dB dB dB dB 02 . 26 : Returnloss 02 . 26 : Isolation 2 : Couping 02 . 6 : ty Direcativi 7.3. 8.34/ 20 13 14 31 42 22 2 12 21 34 43 8.34 20log 10 0.38282 00 0.83282 90 1 1 0.92382 0.92382 0 Cd B j SSSS j j j           Let 1 1 V (reference) ' 122 1 1 1 ' 433 1 1 1 '' ' 24 2 4 1 2 1 '22 2 ' 32 3 1 3 3 4 '0 3 0.9238 0 ( ) 0.382 90 ( ) (0.382 90 )(0.382 90 ) (0.9238)(0.9238) 0.70748 (0.9238)(0.382 90 ) (0.382 90 )(0.9238) 0.707315 90 VVS V V V V VV S V S V S V S V  
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This note was uploaded on 12/14/2010 for the course EEE 445 taught by Professor Georgepan during the Fall '10 term at ASU.

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EEE445_hw11sln - EEE 591/445 Homework 11 6.22. Solution 1....

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