Prob 8-29 Fig 8-84 solved - mesh_loop

# Prob 8-29 Fig 8-84 solved - mesh_loop - @I1: 2 - I1*R1 –...

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Prob 8-29 Fig 8-84 Use mesh analysis to solve for loop currents. Use results to determine I and Vab Notice that it appears there are three loops. If you write those three equations and enter them in  the calculator to solve, it is indeterminant! The reason is the three loops are not independent.  One way to see this is to delete one of the outer shorts and you will see the connectivity of the  circuit is not changed. Any one of them can be removed or any two equations can be written. Doing the selected loops:

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Unformatted text preview: @I1: 2 - I1*R1 – I1*R3 + I2*R3 – 12 = 0-I1*40 – I1*60 + I2*60 = 12 -2 I1(-100) + I2(60) = 10 @I2: 12 – I2*R3 + I1*R3 – I2*R2 + 8 = 0 20 – I2*60 + I1*60 – I2*80 = 0 I1(60) + I2(-60 – 80) = -20 I1(60) + I2(-140) = -20 Solving in the calculator yields: I = I1 = -0.0192 A = -19.2 mA ; I2 = 0.135 A Vab = E3 + I1*R3 – I2*R3 = 12 + R3(I1 – I2) = 12 + 60(-0.0192 - 0.135) = 12 - 60*154E-3 = = 12 – 9.25 = 2.75 V (= 2.77 V in Multisim)...
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## This note was uploaded on 12/14/2010 for the course ECET 107 taught by Professor Huehne,karl during the Spring '09 term at IUPUI.

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Prob 8-29 Fig 8-84 solved - mesh_loop - @I1: 2 - I1*R1 –...

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