Prob 11-8 Fig 11-51 solved

Prob 11-8 Fig 11-51 solved - -10t )))/10E3 = (-20 + 20 -...

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Prob 11-8 Fig 11-51 The switch is closed at t = 0s. Determine the equations for the capacitor voltage and current.  Compute vc and ic at t = 50 ms. C = 10  μ F   Initially vc and ic =0. τ  = RC = 10E3*10E-6 = 100E-3 = 100 ms = 0.1 s vc =  -20(1 - e -t/ τ )= -20(1 - e -t/0.1 )=  -20(1 - e -10t ) V    ic = (-20 – vc)/R = (-20 –(-20(1 - e
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Unformatted text preview: -10t )))/10E3 = (-20 + 20 - 20e-10t )/10E3 = - (20e-10t )/10E3 ic = -(20/10E3) e-10t A or -2e-10t mA at t = 50 ms: vc = -20(1 - e-10t ) = -20(1 - e-10*50E-3 ) = -20(1 - e-0.5 ) = -20(1-0.607) = -20*0.393 = -0.787 V ic = -2e-0.5 = -2*0.607 = -1.21 mA...
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This note was uploaded on 12/14/2010 for the course ECET 107 taught by Professor Huehne,karl during the Spring '09 term at IUPUI.

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