Prob 14-6 Fig 14-40 solved

Prob 14-6 Fig 14-40 solved - Since I = 0 then vR must also...

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Prob 14-6 Fig 14-40 Close the switch at t = 0 s and determine iL and vL at t = 0+ s and t = . At t = 0-, the switch is, by definition, open and therefore iL = 0 A. Since the operation of an inductor is defined by v = L di/dt, the current cannot change instantaneously and therefore the current, iL, at t = 0+ must also be 0 A.
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Unformatted text preview: Since I = 0, then vR must also = 0 V via Ohm’s Law. By KVL, vL = 18 V . At t = ∞ , by definition, all currents and voltages have settled down and are not changing. Therefore di/dt = 0 and thus vL = 0 V . Applying KVL yields that vR = 18 V. Ii is then determined for Ohm’s Law as iL = vR/R = 18/390 = 46.2 mA ....
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