Prob 15-14 Fig 15-79 solved

Prob 15-14 Fig 15-79 solved - 5.25 cycles = 525 μ s and 1...

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Prob 15-14 Fig 15-79 For the waveform, determine: period, frequency, and peak-to-peak value. By defintion, period is the amount of time for one cycle. The time shown is for more than one  cycle and therefore the number of cycles represented must be determined. Counting out from the left there are 5 ¼ cycles or 5.25 cycles, therefore:
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Unformatted text preview: 5.25 cycles = 525 μ s and 1 cycle = T = 525 μ s/5.25 = 100 μ s . Since f = 1/T = 1/100E-6 = 1/1E-4 = 1E4 = 10000 Hz = 10 kHz From the figure Vp = 75 V; Vp-p = 2*Vp = 2*75 = 150 Vp-p...
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This note was uploaded on 12/14/2010 for the course ECET 107 taught by Professor Huehne,karl during the Spring '09 term at IUPUI.

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