Prob 15-18 Fig 15-80 solved

Prob 15-18 Fig 15-80 solved - i40 = 50 sin 40 ° = 50*0.643...

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Prob 15-18 Fig 15-80 For the waveform determine the equation for I and determine the current at all marked points. The x-axis is given in degrees and Vp (or amplitude) is shown as 50 A. Therefore   i = 50 sin  α  A Substituting in the four values of a from the waveform:
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Unformatted text preview: i40 = 50 sin 40 ° = 50*0.643 = 32.1 A i120 = 50 sin 120 ° = 50*0.866 = 43.3 A i200 = 50 sin 200 ° = 50*-0.342 = -17.1 A i310 = 50 sin 310 ° = 50*-0.766 = -38.3 A...
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This note was uploaded on 12/14/2010 for the course ECET 107 taught by Professor Huehne,karl during the Spring '09 term at IUPUI.

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