Prob 16-22 solved

Prob 16-22 solved - = j188 b. Xl = 2 fL = 2p1000*0.5 =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Prob 16-22  What is the reactance of a 0.5 H inductor at a. 60 Hz, b. 1000 Hz c. 500 rad/s a. Xl  = 2 π fL = 2p60*0.5 
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = j188 b. Xl = 2 fL = 2p1000*0.5 = j3.14 k c. Xl = L = 500*0.5 = j250...
View Full Document

This note was uploaded on 12/14/2010 for the course ECET 107 taught by Professor Huehne,karl during the Spring '09 term at IUPUI.

Ask a homework question - tutors are online