EEE445_Lectr18_stub_anal_ADS

EEE445_Lectr18_stub_anal_ADS - Analytic and ADS solutions...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Analytic and ADS solutions Smith chart is handy, but only for a single frequency or narrow band. Analytic approach provides solutions in a given bandwidth. Solving quadratic algebraic equation (next page). May convert into a simple program, e.g., Matlab Based on Smith/analytic solution, ADS may finalize the design, layout and implementation EEE 591/445 Lecture 18 1
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Shunt Double-Stub Matching: Design Equations ( 29 d t β tan = ( 29 ( 29 2 2 0 1 2 0 2 2 0 2 1 0 0 sin L L L L Y B t B t t G G Y t t Y G d - - + - + = ( 29 ( 29 t G Y G t G Y G t Y B t t G Y G t Y B B L L L L L L L 0 2 2 0 2 0 2 2 2 0 2 0 1 1 1 + - + ± = - + ± + - = EEE 591/445 2 Lecture 18 Basic equations (5.19) (5.22) (5.23) (5.21)
Background image of page 2
Shunt Double-Stub Matching: Design Equations - = = S s S o B Y l Y B l 0 0 tan a 2 1 : n realizatio stub circuit - Short tan a 2 1 : n realizatio stub circuit - Open π λ If either length is negative simply add λ /2 to give a physically realizable length. 2 1 or B B B S = EEE 591/445 3 Lecture 18 (5.24a) (5.24b)
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
function [d,ls] = stub1_shsc(zL) % design single-stub matching networks to match normalized load impedance % uses shunt SC stub % % inputs % zL = normalized load impedance % % outputs % d(i) = distance in wavelengths from load to stub; two solutions i=1,2. % ls(i) = length of SC stub; two solutions i=1,2. % initialize the variables d = NaN*ones(1,2); ls = NaN*ones(1,2); t = NaN*ones(1,2); rL = real(zL); xL = imag(zL); % determine values of d using (5.9) and (5.10) if rL==1, t(1) = -xL/2; else t(1) = (xL + sqrt(rL*((1-rL)^2+xL^2)))/(rL-1); t(2) = (xL - sqrt(rL*((1-rL)^2+xL^2)))/(rL-1); end d = atan(t)/(2*pi); k = find(d<=0);
Background image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2010 for the course EEE 445 taught by Professor Georgepan during the Fall '10 term at ASU.

Page1 / 17

EEE445_Lectr18_stub_anal_ADS - Analytic and ADS solutions...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online