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Unformatted text preview: PHYS 253: Assignment 3 Problem 1 For this hydrostatic system, the first law is dU = dQ PdV dU = emf I dt p dV Integrating, we get U = emf I t p ( nv o V ) Problem 2 a) We write the 1st law as dQ = dU + PdV Keeping in mind that U = U ( P,T ), we can rewrite dU as dU = U T P dT + U P T dP and from the EOS, we write PdV as PdV = P V T P dT + V P T dP Regrouping the terms, we get dQ = U T P + P V T P dT + U P T + P V P T dP b) setting P to be a constant, we rewrite the expression from a) as dQ dT P = U T P + P V T P Rewriting the individual terms: dQ dT P = C P and P V T P = PV we finally get U T P = C P PV 2 c) Starting from the expression in a), at constant V , we first use the result from b) to rewrite the U T  P term dQ = C P dT + U P T + P V P T dP and now rewriting the V P  T using the definition of , and dividing by dT , we get:...
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 Fall '10
 PeterGrutter
 Thermodynamics

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