Lecture%2019%20March%2026%20%28Chapter%2021%20--%20Electrochemistry%29-1

Lecture%2019%20March%2026%20%28Chapter%2021%20--%20Electrochemistry%29-1

Info iconThis preview shows pages 1–18. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Chapter 21 -- Electrochemistry Lecture 19 March 26, 2009 What is G o of the cell reaction described by the equation below? Cd (s) + 2Ag + (aq) Cd 2+ (aq) + 2Ag ( s) Standard Reduction Potential E o (V) Cd 2+ (aq) + 2e- Cd (s)-0.403 Ag + (aq) + e- Ag (s) +0.7996 F = 96485.34 C/mol, 1 Joule = C/V, G o = -nFE o (A) -76.53 kJ/mol (A) +76.53 kJ/mol (A) +232.1 kJ/mol (A) -232.1 kJ/mol The equilibrium constant for the redox reaction shown below, at 298K, is Cd (s) + 2Ag + (aq) Cd 2+ (aq) + 2Ag ( s) Standard Reduction Potential E o (V) Cd 2+ (aq) + 2e- Cd (s)-0.403 Ag + (aq) + e- Ag (s) +0.7996 E o = (0.0592V/n)logK (A) a very small number (A) zero (A) one (A) a very large number Consider the following non-aqueous cell reaction 2Na (l) + FeCl 2 (s) 2NaCl (s) + Fe (s) for which E o cell = 2.35V at 200 o C. What is G o at this temperature? F = 96485.34 C/mol A.453 kJ B.-453 kJ C.907 kJ D.-907 kJ Ow!!! Dont chew on Aluminum Foil if you have dental fillings electrochemistry explains why it is so painful!electrochemistry explains why it is so painful!...
View Full Document

This note was uploaded on 12/15/2010 for the course PHYS 0001 taught by Professor Nayak during the Spring '10 term at Rensselaer Polytechnic Institute.

Page1 / 20

Lecture%2019%20March%2026%20%28Chapter%2021%20--%20Electrochemistry%29-1

This preview shows document pages 1 - 18. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online