Exam 2 Solutions

Exam 2 Solutions - RA $1 1 VT VF = HEEL 15A...

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Unformatted text preview: RA $1: 1+ VT ; , VF = HEEL __. 15A 5NoteaA=>VT=EA EF+QRAd 320.51. - Fm ’dm, mangatam awe , IF Cow-W TS 5A0 = 3?5V [email protected] n,_—_ EA = 3- => n: 360V 4000er = 5160.. m EAL) no 375V ‘— 2 C) Er \szlygov 7 n 2 leoorPM: $ A5 finaeWL; I; / (4.96“:wa =>33=IFNF / £7¢=ILJ =~=> w: EA / W, 1%; LiL R Kg @r W W of 1% wvétar‘tb 1mm cm ‘24 [a maximiz-gql. @110 =160£L /2 ——->IF.—. 45...: me v.2,“ ?.=+2aad. 49051 . a: 679014:an = AK. =2) 1F =IF, i:fi =112A — W me‘lh amt: (3m m..a.£w Mfrgaom 31mm. flu}; La .‘Um Lime.» refiimv) 9: = “2.5V Eff; 'A—QA: VT— \LRA :: _ (SEA-)(O.Z.Q—B :: 3§0V n: EiJw = 390" xtooo Irma-‘3“! m age 0 Oil-.3“ r? A ,0 5211321. iPE’ Z=2CN¢= Qxféxg‘z-Qgé «=2? =8 30, a): 24V$2TC><8 ___. % 44.!1 rad/Sec (9P 256x H'XIZS-XIO'B b) I”: .1; 4w =2A £71M=K¢I siflgzl'fl ‘1’?ng x 540’sz 31'ng /0” él‘ven: V; = 120V Zak»: 0.01.1600. .5). 20¢: —Q. (a) Mmf in {in M yeah? , l/flfi VA-Vg: V5Z2°— Vs l4 .— V; 093120"? Vs gin. I20° == 1/:3—VS ['30" V a' .r —— E E 3* % aw ; 0.01 min = 0.005 +3o.ooggé IL iiinrM =10.005+3 [470864.191 10.0é 15%" .0. ~ 120V 30, ’IL) = mom. all/13A I2 (6) How mac!» [faBZrSZLJOWMd 120:, 244% .7 4324.“; f . Fm: 3152M on: em = 3(M3A)Z(aazn)mw 21. 2.13 w QM r. 312; 2m fined“ SJ; 5-70 m,» 314e, = 3112qu. = 4.24 VA 0 Flood == 3Iiiaod—w: 94.4 = 3(”“73A):{”’00+1lfl)“5fl“flfi :1- 4270 W 10.05 (PM: 31129;»! Shaw 2‘ 42? Vatr Smuizw s 4267/ VA (00 mat in {Zefznemé‘r’s W 7407351, ,7 = $03 9 —_—, Cog (fan—1 : (10$ (‘3;«4 W Puma + PM = cos (Eff, 3: avg (5,7573% QZWIIBW ! i Ema (£3 = $5M w Sm (mt = 1? gm 10’0" [:7 wz10mJ/Aec gm: 1.5‘ wt» .—.— B.A = e (mm "9 W-"—' b =0~§m=50c¢m - 5T: 0'6?“ Wm ...
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Exam 2 Solutions - RA $1 1 VT VF = HEEL 15A...

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