# ITEC1000 - ITEC1000"Introduction to Information...

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ITEC1000 "Introduction to Information Technologies" Assignment #1 1) Convert numbers to binary: (5 pts. ea.) 1) a) 1000011111111 2 b) 101001101.11001 2 c) 10100101010010101 2 1.a 4607 10 = 1000111111111 2 4607 / 2 = 2303 remainder 1 2303 / 2 = 1151 remainder 1 1151 / 2 = 575 remainder 1 575 / 2 = 287 remainder 1 287 / 2 = 143 remainder 1 143 / 2 = 71 remainder 1 71 / 2 = 35 remainder 1 35 / 2 = 17 remainder 1 17 / 2 = 8 remainder 1 8 / 2 = 4 remainder 0 4 / 2 = 2 remainder 0 2 / 2 = 1 remainder 0 1 / 2 = 0 remainder 1 1.b 333.25 10 = 101001101.01 2 333 / 2 = 166 rem 1 And 0.25 166 / 2 = 83 rem 0 x 2 83 / 2 = 41 rem 1 0.50 41 / 2 = 20 rem 1 x 2 20 / 2 = 10 rem 0 -------- 10 / 2 = 5 rem 0 1.00 5/ 2 = 2 rem 1 2 / 2 = 1 rem 0 1 / 2 = 0 rem 1 1.c 0.84629 10 = 0.11011.. 2 0.84629 x 2 1.69258 x 2 1.38516 x 2 0.77032 x 2 1.54064 x 2 1.08128 2) Convert numbers to decimal: (5 pts. ea.) a) 117 10 b) 23.3 10 c) 0.23 10 2.a 1110101 2 = 2 6 + 2 5 + 2 4 + 2 2 +2 0 = 64 + 32 +16+ 4 + 1 = 117 10 2.b 10111.011 2 = 23.375 10 10111 2 = 2 4 + 2 2 + 2 1 +2 0 = 23 10 And 0.011 2 = 2 -2 + 2 -3 = 0.375 10 2.c 0.10111 2 = = 2 -1 + 2 -3 + 2 -4 + 2 -5 = 0.5 + 0.125 + 0.0625 + 0.03125 = 0.71875 10 3) Convert numbers to binary: (5 pts. ea.) a) 1011100111100111 2 b) 10101000.11010110 2 c) 0.110011001111 2 3.a B9E7 16 = 1011100111100111 2 B 16 = 1011 2 9 16 = 1001 2 E 16 = 1110 2 7 16 = 0111 2 3.b A8.D6 16 = 10101000.11010110 2 A 16 = 1010 2 8 16 = 1000 2 D 16 = 1101 2 6 16 = 0110 2 3.c 0.C3F 16 = 0.110000111111 2 C 16 = 1100 2 3 16 = 0011 2 F 16 = 1111 2 4) Convert numbers to hexadecimal: (5 pts. ea.) a) 6FC 16 b) 16.0D 16 c) 0.2B 16

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