L05_Axial Deformations-10

L05_Axial Deformations-10 - EAS 209-Fall 2010 Instructors:...

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EAS 209-Fall 2010 Instructors: Christine Human 8/24/2010 1 05-Axial Deformation Lecture 5 Deformations of Members Under Axial Loading We learned last lecture that provided a material remains in the linear elastic region, stress is proportional to strain ε σ = E Since σ =P/A and ε = δ /L we can rewrite the above equation to solve for the deformation: AE PL = δ where P is the applied axial load L is the length of the member A is the cross-sectional area E is the elastic modulus of the material Today’s Objective: Calculate the deformation of axially loaded members Today’s Homework: EAS 209-Fall 2010 Instructors: Christine Human 8/24/2010 2 05-Axial Deformation Stiffness and flexibility of a bar are defined in the same way as for a spring Spring Bar Flexibility, f Stiffness, k fP = f -flexibility k P = k -stiffness AE L f = L AE f k = = 1 Unless specified, prismatic bars are assumed to have the same stiffness in compression and tension.
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This document was uploaded on 12/19/2010.

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L05_Axial Deformations-10 - EAS 209-Fall 2010 Instructors:...

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