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Unformatted text preview: t; 0, z = 0 and z = 2x1 − 3x2  so the objective function will equal z + z = z = 2x1 − 3x2 . z and z cannot both be in the basis at the same time. This problem is unbounded. z = z = c > 0 (x1 , x2 ) = (0, 0) is feasible and the objective value is 2c. IOE 310 – Problem Set 06  Solution Page 2 of 2 Problem 2
Section 6.1 Problem 5 (p.267) 1 (a) Let c1 = proﬁt from type 1 radio. Slope of isoproﬁt line is c2 . Current basis is still optimal if of iso1 proﬁt line is steeper than L1 constr...
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 Fall '08
 Saigal

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