EECS 215 F07 Problem Set 6 solutions

EECS 215 F07 Problem Set 6 solutions - HW 6, Problem 1,...

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0 1 2 3 4 5 6 7 8 9 10 -1 0 1 2 3 4 5 6 7 8 9 v in (V) v out HW 6, Problem 1, part b %EECS 215 HW 6 Problem 1, Part b clear all ; vina = linspace(0,1,100); vinb = linspace(1,10,900); vouta = vina.*0; voutb = -0.2.*(sqrt(vinb-0.99)-5.*(vinb-0.98)); vout = [vouta, voutb]; vin = [vina, vinb]; plot(vin,vout);
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0 1 2 3 4 5 6 7 8 9 10 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 v in (V) dv out /dv Hw 6 question 1 part b (2) %EECS 215 HW 6 Problem 1, Part b second part clear all ; vin = linspace(1,10,1000); derivative = -0.2.*(0.5./sqrt(vin-0.99)-5); plot(vin,derivative);
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2 a: Code for part A. %EECS 215 Fall 2007 HW6 Problem 2, part a clear all ; Vcc=10; K=5e-3; VT=1; % amp with source resistance R1=50e3; R2=250e3; VGS=0:1e-3:8.5; RT=R1+ R2; VGS_LIN=VT-1/(K*RT)+sqrt((1/(K*RT))^2+2/(K*RT)*Vcc) for jj=1:length(VGS), if VGS(jj)<VT, % transistor off ID(jj)=0; end ; if VGS(jj)>=VT & VGS(jj)<VGS_LIN, % saturation mode ID(jj)=0.5*K*(VGS(jj)-VT)^2; end ; if VGS(jj)>=VGS_LIN, % triode/linear mode vds1=(VGS(jj)-VT+1/(K*RT))-sqrt((VGS(jj)-VT+1/(K*RT))^2-2/(K*RT)*Vcc); ID(jj)=K*((VGS(jj)-VT)*vds1-vds1^2/2); end ; Vin(jj)=VGS(jj)+R1*ID(jj); Vout(jj)=Vcc-R2*ID(jj); VDS(jj)=Vcc-RT*ID(jj); end ; subplot(2,1,1); plot(Vin,Vout, 'linewidth' ,2); set(gca, 'fontsize'
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EECS 215 F07 Problem Set 6 solutions - HW 6, Problem 1,...

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