ee250_HW8_sol

ee250_HW8_sol - EE 250 SOLUTIONS TO HOMEWORK 8 Pr 1. [10...

This preview shows pages 1–7. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
SOLUTION

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
SOLUTION The network above can be simplified into the following two 2-port networks in series Network A Network B When two 2-port networks are connected in series, the Z-parameters of the combined network are merely the sum of the Z-parameters of the individual networks. 2 11 21 2 21 12 1 0 12 21 1 2 For Network A, (2 4) (2 4) 3 (because the network is all-passive and hence, reciprocal) To find , consider that at node x, the current splits equally into and 22 equ I z z V zz I II zI V = =+ +=Ω = == 1 1 1 1 2' 1 1 1 21 als the potential difference between nodes y and y' The potential at node y equals 2 2 The potential at node y' equals 4 2 2 () ( 2 ) Therefore, xx yy x x I VV I I I VVV VI V I I ⎛⎞ −× =− ⎜⎟ ⎝⎠ =−= −− − = = 2 2 12 1 0 1 I V I =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
11 21 12 Network B is a T-network As demonstrated in class, for a T-network with three branches , and , (where is the middle branch), then the Z-parameters of the T-network are given by ; AB C B ZZ Z Z zZZ zz =+ == 22 11 22 21 12 11 11 11 22 ; Therefore, for network B, 1 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/20/2010 for the course E E 240 taught by Professor Shankar during the Spring '10 term at University of Alberta.

Page1 / 11

ee250_HW8_sol - EE 250 SOLUTIONS TO HOMEWORK 8 Pr 1. [10...

This preview shows document pages 1 - 7. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online