10_08_Circular_Motion

10_08_Circular_Motion - 10/8 Circular Motion 0 Text:...

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10/8 Circular Motion 0 Text: Chapter 5 Circular Motion 0 HW 10/8 “Rotating Drum” due Thur 10/11 0 Suggested Problems: Ch 4: 56, 58, 60, 74, 75, 76, 79, 102 0 Exam II Thursday Oct. 18 5-7 PM Wit 116 Exam III Nov 8 or 15? Exam IV Nov 29 or Dec 6?
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Jack pulls the box at constant speed Draw a FBD of the box. W E,B N F,B a = 0 T S,B f F,B Box Since a = 0, F net = 0 and T S,B = f F,B = μ k N F,B v = Jack pulls harder, what happens?
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Kinetic Friction Jack pulls harder Draw a FBD of the box. W E,B N F,B a = T S,B f F,B Box v = The tension force increases but the kinetic friction force stays the same! Kinetic friction does not depend on velocity or acceleration. f F,B = μ k N F,B F net = T S,B - f F,B = ma x y
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speed Draw a FBD of the box. W E,B N F,B a = 0 f F,B Box v = How will the string angle change the FBD? 30° Tension force now has a vertical component which means N F,B is smaller. f
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This note was uploaded on 12/21/2010 for the course PHYS Physics 21 taught by Professor Larrywatson during the Fall '08 term at North Dakota.

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10_08_Circular_Motion - 10/8 Circular Motion 0 Text:...

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