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10_24_Momentum_2 - 10/24 Momentum 2 0 0 0 0 Text Chapter7...

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10/24 Momentum 2 0 Text: Chapter7 0 Presentation “Car and Parked Truck” 0 HW “Energy and Momentum” Due Friday 0 Peer Guides: Please keep a rough tally of the number using the Guidance Center 0 Exam II: Average = 76%!! 0 Deficiencies: post scores by NAID# on door Check my records, highlighted = see me!
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Car collides with a parked truck on glare ice, (frictionless). A B m A = m m B = 6m v v = 0 C m C = m v, same as A After A and B collide, C collides with B and B comes to rest again. After A and B collide, A is moving left at 1 / 2 v What happens to B? Could we use 2nd law? Energy? Momentum? m A v i,A + m B v i,B = m A v f,A + m B v f,B F net t = p 3rd law pairs A B During collision A and B N B,A N A,B before A B m A = m m B = 6m v/2 v = ? C m C = m v, same as A after
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Car collides with a parked truck on glare ice, (frictionless). A B m A = m m B = 6m v v = 0 C m C = m v, same as A After A and B collide, C collides with B and B comes to rest again. A B m A = m m B = 6m v/2 v = ?
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