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Unformatted text preview: h R T g S R T g S Must be a 50/50 split of the PE g KE T = 1 / 2 PE g 1 / 2 mgh = 1 / 2 mv 2 v = gh How do we find the acceleration? t x v ave = x a = v t t = x v ave v ave = gh 2 v = gh Because its a ring!!!! More off to the Races. Find the velocity of the disk at the bottom, then find the acceleration. h R T g S Pe g split 1 / 3 : 2 / 3 R T g S How do we find the acceleration? t x v ave = a = v t t = x v ave KE T = 2 / 3 PE g 2 / 3 mgh = 1 / 2 mv 2 3 v = 4gh 3 v ave = 4gh 2 3 v = 4gh x Because its a disk!!!!...
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This note was uploaded on 12/21/2010 for the course PHYS Physics 21 taught by Professor Larrywatson during the Fall '08 term at North Dakota.
 Fall '08
 LarryWatson
 Physics, Energy

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