11_29_SHM_2

# 11_29_SHM_2 - 11/29 Simple Harmonic Motion Presentation...

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11/29 Simple Harmonic Motion / Presentation “Horizontal vs Vertical SHM” / HW “Simple Harmonic Motion 2” Due Wednesday 12/5 / Exam IV Thursday Eve 12/6 5-7 Wit 116 Angular Momentum Simple Harmonic Motion

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Prototype system: block on a horizontal frictionless surface attached to a spring that can push as well as pull
Hooke’s Law = Simple Harmonic Motion F Spring = -k x “Simple” harmonic motion only when the force is proportional to the displacement, x, as in Hooke’s law. x is displacement (compression or extension) from equilibrium. Force always points toward the equilibrium position.

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Problem A 0.05kg mass hangs from a spring and is found to stretch the spring by 5cm from its unstretched length. What is the spring constant of the spring? unstretched length equilibrium position ( x eq ) mg = k x eq T S,M W E,M
SHM characterized by: / Period (T) / How long it takes to go through one cycle (sec.) / Frequency (f) / Number of cycles in a second (Hz) / Amplitude (A) / Maximum distance from equilibrium (meters)

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1.75 m 0.25 m 0.25 m Where is the equilibrium position? What is the amplitude of the
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11_29_SHM_2 - 11/29 Simple Harmonic Motion Presentation...

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