BuffferExpSampleCal

# BuffferExpSampleCal - 0.00400 mol HA 0.0300 mol HA =...

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Experiment 8 Buffers Sample Calculations Pipet 40.00 mL of your assigned weak acid solution into a 150-mL beaker. Add 30.00 mL of 0.100 M NaOH and 10.00 mL of degassed deionized water with pipets and mix thoroughly. The resulting solution is Buffer II. Either of the following methods would earn full credit to show your logic for determining [HA] and [A 1= ]. Method I starting mole HA = 0.04000 L × 0.100 mol HA L = 0.00400 mol HA mole NaOH = 0.03000 L × 0.100 mol NaOH L = 0.00300 mol NaOH added mol NaOH added = mol HA consumed = mol A 1- produced

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Unformatted text preview: 0.00400 mol HA 0.0300 mol HA = 0.00100 mol remaining [HA] = 0.00100 mol HA 0.08000 L = 0.0125 M HA [A 1-] = 0.00300 mol A 1-0.08000 L = 0.0375 M A 1- Method II starting mole HA = 0.04000 L 0.100 mol HA L = 0.00400 mol HA 0.03000 L 0.100 mol NaOH L 1 mol HA 1 mol NaOH = 0.00300 mol HA consumed 0.00400 mol HA 0.0300 mol HA = 0.00100 mol remaining 0.00300 mol HA 1mol A 1-1 mol HA = 0.00300 mol A 1-produced [HA] = 0.00100 mol HA 0.08000 L = 0.0125 M HA [A 1-] = 0.00300 mol A 1-0.08000 L = 0.0375 M A 1-...
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## This note was uploaded on 12/21/2010 for the course CHEM 1B taught by Professor Garyj.decicco during the Fall '10 term at Santa Rosa.

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BuffferExpSampleCal - 0.00400 mol HA 0.0300 mol HA =...

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