EE115 Homework Assignment 1

# EE115 Homework Assignment 1 - Introduction to Alternating...

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Unformatted text preview: Introduction to Alternating Current and Voltage Calculate the frequency from the following period. Period (T) 4ms 200μs 80ms 50ms 1ms Frequency 250 Hz 500 KHz 12.5 Hz 20 Hz 1 KHz Calculate the period (T) from the following frequency. Frequency 60 Hz 40 Hz 1500 Hz 2400 Hz 4000 Hz Period (T) 17ms 25 ms .667 ms .41 ms .25 ms Calculate the peak voltage from the peak to peak voltage Peak to Peak Voltage 120 Vpp 45 Vpp 15 Vpp 85 Vpp 6.5 Vpp Peak voltage 60Vp 22.5Vp 7.5Vp 2.5Vp 3.25Vp Calculate the peak to peak voltage from the peak voltage Peak Voltage 35 Vp 120 Vp 40 Vp 3.6 Vp 17.8 Vp Peak to Peak Voltage 70Vpp 240Vpp 80Vpp 7.2Vpp 35.6Vpp Calculate the rms voltage from the peak to peak voltage Peak to Peak Voltage 100 Vpp 80 Vpp 20 Vpp 120 Vpp 65 Vpp rms Voltage 35.35 rms voltage 28.28 rms voltage 7.07 rms voltage 42.42 rms voltage 22.98 rms voltage Calculate the peak to peak voltage from the rms voltage rms voltage 120 rms volts 65 rms volts 85 rms volts 40 rms volts 15 rms volts Peak to Peak Voltage 339.46Vpp 183.88Vpp 240.45Vpp 113.15Vpp 42.43Vpp Calculate the average voltage from the peak voltage Peak Voltage 30 Vp 140 Vp 65 Vp 4.6 Vp 28.8 Vp Average Voltage 38.28Vavg 89.32Vavg 41.47Vavg 2.9Vavg 18.37Vavg Calculate the average voltage from the peak voltage Peak Voltage Average Voltage 30 Vp 38.28Vavg 140 Vp 89.32Vavg 65 Vp 41.47Vavg 4.6 Vp 2.9Vavg 28.8 Vp 18.37Vavg Calculate the peak voltage from the number of volts per division and number of units on th vertical axis on the oscilloscope screen Volts per Division 5 volts per division 1 volts per division .1 volts per division Number of Divisions from peak to peak 6.2 divisions 4.8 divisions 3.1 divisions .5 volts per division .01 volts per division 2.6 divisions 1.5 divisions Calculate the period of a sine wave from the time per division setting and number of units o horizontal axis that the sine wave uses on the oscilloscope screen. Time per Division 5ms per division 1ms per division .1ms per division .5ms per division 5μs volts per division Number of Divisions for one sine wave 4.2 divisions 6.8 divisions 5.1 divisions 3.6 divisions 2.5 divisions Calculate the instantaneous voltage of a sine wave from the angular position (degrees) and peak voltage (Vp) Angular position in degrees 120 90 45 270 210 Peak voltage 45 Vp 60 Vp 10 Vp 110 Vp 30 Vp 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 Place the letter representing the correct definition for each in this column. Use the Definition Choices Table to select correct definition. P E A G B K T I M S L R Q H C J F 18 19 20 N D O Definitions Choices Table A B C D E F G H I J K The maximum value of a voltage or current A measure of the rate of change of a periodic function; the num cycles completed in 1 s. A unit of angular measurement. There are 2Π radians in one c 360° revolution. A measurement instrument that displays signal waveforms on screen. An electronic circuit that produces a time-varying signal withou external input signal using positive feedback. An instrument that produces more than one type of waveform. The unit of angular measure corresponding to 1/360 of a comp revolution. The rotational rate of a phasor that is related to the frequency sine wave that it represents. The voltage or current value of a waveform at its maximum po negative points. The time interval of one complete cycle of a periodic waveform Periodic Characterized by a repetition at fixed-time intervals. The average of a sine wave over one half-cycle. It is 0.637 tim peak value. Cycle One repetition of a periodic waveform. L M N O P Q R The voltage or current value of a waveform measured from its minimum to its maximum points. The pattern of variations of a voltage or current showing how t quantity changes with time. A type of waveform that follows a cyclic sinusoidal pattern defi the formula y = A sin θ. The voltage or current value of a waveform at a given instant i The unit of frequency. One hertz equals one cycle per second A type of waveform characterized by a linear increase or decre voltage or current. The value of a sinusoidal voltage that indicates its heating effe known as the ef¬fective value. It is equal to 0.707 times the pe value. rms stands for root mean square. S T A representation of a sine wave in terms of its magnitude (amp and direction (phase angle). The time interval required for a pulse to change from 10% to 9 its amplitude. ision and number of units on the Peak voltage 31V 4.8V .31V 1.3V .015V on setting and number of units on the screen. Period for sine wave 21ms 7ms 1ms 2ms 125μs e angular position (degrees) and the Instantaneous voltage 38.97V 60V 7.07V 110V 15V ing the correct definition for each term efinition Choices Table to select the Terms Hertz (Hz) Oscillator Amplitude Degree Frequency (/) Average value Rise time (Tr) Peak value Waveform Phasor Peak-to-peak value rms value Ramp Angular velocity Radian Period (T) Function generator Sine wave Oscilloscope Instantaneous value ltage or current ange of a periodic function; the number of ent. There are 2Π radians in one complete that displays signal waveforms on a duces a time-varying signal without an positive feedback. s more than one type of waveform. e corresponding to 1/360 of a complete sor that is related to the frequency of the . e of a waveform at its maximum positive or plete cycle of a periodic waveform. repetition at fixed-time intervals. over one half-cycle. It is 0.637 times the tition of a periodic waveform. e of a waveform measured from its oints. a voltage or current showing how the lows a cyclic sinusoidal pattern defined by e of a waveform at a given instant in time. hertz equals one cycle per second. terized by a linear increase or decrease in oltage that indicates its heating effect, also ue. It is equal to 0.707 times the peak ean square. ave in terms of its magnitude (amplitude) . or a pulse to change from 10% to 90% of ...
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